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55^2+h^2=73^2
We move all terms to the left:
55^2+h^2-(73^2)=0
We add all the numbers together, and all the variables
h^2-2304=0
a = 1; b = 0; c = -2304;
Δ = b2-4ac
Δ = 02-4·1·(-2304)
Δ = 9216
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$h_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$h_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{9216}=96$$h_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-96}{2*1}=\frac{-96}{2} =-48 $$h_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+96}{2*1}=\frac{96}{2} =48 $
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